1. 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
A. 9
B. 10
C. 11
D. 12
Answer: Option D
Explanation:
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps | 4 | : | 3 | :: 8 : x | |
Days | 1 | : | 2 |
4 x 1 x x = 3 x 2 x 8
x = | (3 x 2 x 8) |
(4) |
x = 12.
2. If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
A. |
| B. | Rs. (xd) | |||||
C. | Rs. (yd) | D. |
|
Answer: Option D
Explanation:
Cost of x metres = Rs. d.
Cost of 1 metre = Rs. | d | ||
x |
Cost of y metres = Rs. | d | . y | = Rs. | yd | . | |||
x | x |
3. Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A. 648
B. 1800
C. 2700
D. 10800
Answer: Option B
Explanation:
Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines | 6 | : | 10 | :: 270 : x | |
Time (in minutes) | 1 | : | 4 |
6 x 1 x x = 10 x 4 x 270
x = | (10 x 4 x 270) |
(6) |
x = 1800.
4. A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food willlast, is:
A. |
| B. |
| ||||||
C. | 42 | D. | 54 |
Answer: Option C
Explanation:
After 10 days : 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
125 : 150 :: 35 : x 125 x x = 150 x 35
x = | 150 x 35 |
125 |
x = 42.
A. 10
B. 13
C. 14
D. 15
Answer: Option B
Explanation:
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons | 30 | : | 39 | :: 12 : x | |
Working hours/day | 6 | : | 5 |
30 x 6 x x = 39 x 5 x 12
x = | (39 x 5 x 12) |
(30 x 6) |
x = 13.
6. A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
A. | 5 | B. | 6 | |||
C. | 7 | D. |
|
Answer: Option B
Explanation:
Work done = | 5 |
8 |
Balance work = | 1 - | 5 | = | 3 | ||
8 | 8 |
Let the required number of days be x.
Then, | 5 | : | 3 | = :: 10 : x | 5 | x x = | 3 | x 10 | |
8 | 8 | 8 | 8 |
x = | 3 | x 10 x | 8 | ||
8 | 5 |
x = 6.
7. If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?
A. 48 paise
B. 54 paise
C. 56 paise
D. 72 paise
Answer: Option A
Explanation:
Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
250 : 200 :: 60 : x 250 x x = (200 x 60)
x= | (200 x 60) |
250 |
x = 48.
8. In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?
A. | 1 | B. |
| ||
C. | 40 | D. | 80 |
Answer: Option C
Explanation:
Let the required number of days be x.
Less cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
Cows | 1 | : | 40 | :: 40 : x | |
Bags | 40 | : | 1 |
1 x 40 x x = 40 x 1 x 40
x = 40.
9. A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions mad by the larger wheel is:
A. 4
B. 9
C. 12
D. 49
Answer: Option B
Explanation:
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
14 : 6 :: 21 : x 14 x x = 6 x 21
x = | 6 x 21 |
14 |
x = 9.
A. | 1 | B. |
| ||
C. | 7 | D. | 49 |
Answer: Option C
Explanation:
Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
Spiders | 1 | : | 7 | :: 7 : x | |
Webs | 7 | : | 1 |
1 x 7 x x = 7 x 1 x 7
x = 7
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